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Indicate the number of unpaired electron in (a) P (b) Si (c) Cr (d) Fe, and (e) Kr |
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Answer» Solution :(a) `._(15)P = 1s^(2) 2S^(2) 2p^(6) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)`. No of unpaired electron = 3 (b) `._(14)Si = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(y)^(1)`. No of unpaired electrons = 2 (c) `._(24)Cr = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3d^(5) 4s^(1)`. No of unpaired electron = 6 (d) `._(26) FE = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(6) 4s^(2)`. No of unpaired electron = 4 (in 3 d) (e) `._(36)Kr` = NOBLES gas. All orbitals are filled. Unpaired electrons = 0 |
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