Saved Bookmarks
| 1. |
Initial pressure of XY, is 600 mm Hg. pressure at equilibrium is 800 mm Hg.volume of system to remain constant, thK is(1) 50(3) 20(2) 100(4) 400... pressure of COCI. is 1000 |
|
Answer» XY 2 DISSOCIATES as:XY 2 (g)⇌XY(g)+Y(g)Initial pressure of XY 2 is 600 mm Hg. The total pressure at EQUILIBRIUM is 800 mm Hg.Let X mm Hg of XY 2 dissociates to reach equilibrium. x mm Hg of XY and x mm Hg of Y will be formed at equilibrium. 600−x mm Hg of XY 2 will be present at equilibrium.Total pressure =(600−x)+x+x=600+x mm Hg But total pressure =800 mm Hg 600+x=800 or x=200Thus, the equilibrium pressures areP XY 2 =600−x=600−200=400 mm HgP XY =x=200 mm HgP Y =x=200 mm Hg Assuming volume of system to remain CONSTANT, the value of K p = P XY 2 P XY P Y K p = 400200×200 K p =100 mm |
|