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Initial volume of `H_(2)` gas saturated with water vapour is confined under a piston in a container is 10 litres as shown in the given figure. the container also contains some liquid water. The total pressure over liquid water is `80cm` of `Hg`. If now the piston is removed such that volume of container is doubled, then final total pressure over liqid water in the container is `P`. The vapour pressure of water is `20cm` of `Hg` and volume of liquid is negligible. Calculate `P//10`......... |
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Answer» Correct Answer - 5 `P_(1)V_(1)=P_(2)V_(2)` `P_(2)=` Pressure of `H_(2)` gas `=(60xx10)/20` `P_(2)=30cm` of `Hg` Final total pressure over liquid water `(P)=30+20=50 cm` of `Hg` `P/10=50/10=5` |
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