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Initially car `A` is `10.5 m` ahead of car `B`. Both start moving at time `t = 0` in the same direction along a straight line. The velocity-time graph of two cars is shown in figure. The time when the car `B` will catch the car `A`, will be. A. `t-21` secB. `t=2sqrt(5)` secC. `20` secD. None of these |
Answer» Correct Answer - A `S_(B)=S_(A)+10.5` `t^(2)/2=10t+10.5` `t^(2)=20t+21` `t^(2)-20t-21=0` `t=21` sec |
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