1.

int_0^4(dx)/(sqrt(x^2+9)

Answer»

SOLUTION :`int_0^4(DX)/(SQRT(x^2+9)) =` `int_0^4(dx)/(sqrt(x^2+3^2))`
`=[In(x+sqrt(x^2+3^2)]_0^4`
`=In9-In3=In3`


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