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int_0^4(dx)/(sqrt(x^2+9) |
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Answer» SOLUTION :`int_0^4(DX)/(SQRT(x^2+9)) =` `int_0^4(dx)/(sqrt(x^2+3^2))` `=[In(x+sqrt(x^2+3^2)]_0^4` `=In9-In3=In3` |
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