1.

int_(0)^(pi/2) cos 2x dx

Answer»

SOLUTION :`int_(0)^(pi//2) cos 2X dx=[(sin 2x)/(2)]_(0)^(pi//2)`
`=(1)/(2)[sin 2x]_(0)^(pi//2)`
`=(1)/(2) [(sin 2XX .(pi)/(2))-sin(0)]=(1)/(2) (0-0)=0`


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