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int_(0)^(pi/2) cos 2x dx |
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Answer» SOLUTION :`int_(0)^(pi//2) cos 2X dx=[(sin 2x)/(2)]_(0)^(pi//2)` `=(1)/(2)[sin 2x]_(0)^(pi//2)` `=(1)/(2) [(sin 2XX .(pi)/(2))-sin(0)]=(1)/(2) (0-0)=0` |
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