1.

`int_(0)^((pi)/(2))cos 2x dx`

Answer» `int_(0)^(pi//2)cos 2x dx=[(sin2x)/(2)]_(0)^(pi//2)`
`" "=(1)/(2)[sin2x]_(0)^(pi//2)`
`" "=(1)/(2)[(sin2xx(pi)/(2))-sin(0)]`
`" "=(1)/(2)(0-0)=0`


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