InterviewSolution
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`int_(0)^((pi)/(2))(sinx-cosx)/(1+sinxcosx)dx` |
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Answer» माना `I=int_(0)^(pi//2)(sinx-cosx)/(1+sinxcosx)" …(1)"` `rArr" "I=int_(0)^(pi//2)(sin((pi)/(2)-x)-cos ((pi)/(2)-x))/(1+sin((pi)/(2)-x)cos((pi)/(2)-x))dx` `[because int_(0)^(a)f(x)dx=int_(0)^(a)f(a-x)dx]` `=int_(0)^(pi//2)(cosx-sinx)/(1+cosx sinx)dx" ...(2)"` समीकरण (1 ) और (2 ) को जोड़ने पर `2I=int_(0)^(pi//2)(sinx-cos x+cos x-sinx)/(1+sinx cosx)` `rArr" "I=0` `[because int_(0)^(a)f(x)dx=int_(0)^(a)f(a-x)dx]` |
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