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`int_(0)^((pi)/(4))sin 2x dx` |
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Answer» माना `I=int_(0)^(pi//4)sin 2x dx ` `=int_(0)^(pi//4)2sin x cos x dx` माना `sin x=t" "rArr" "cos x dx = dt` `x=(pi)/(4)" "rArr" "t=sin.(pi)/(4)=(1)/(sqrt2)` `x= 0 " "rArr" "t=sin 0 =0 ` `therefore" "I=2int_(0)^(1//sqrt2)tdt=2[(t^(2))/(2)]_(0)^(1//sqrt2)` `=((1)/(sqrt2))^(2)=(1)/(2)` |
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