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int_0^(pi/4) xsinxdx |
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Answer» Solution :`int_0^(pi/4) xsinxdx` [integrating by PARTS taking xas FIRST and sinx as second function] `[x-(-cosx)]_0^(pi/4)-int_0^(pi/4)(-cosx)DX` `(-pi/4)cos(pi/4)+[sinx]_o^(pi/4)` `(-pi/4)cos(pi/4)+sin(pi/4)-sin0=(1/sqrt2)(1-(pi/4))` |
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