1.

`int_(0)^(pi)|cosx|dx` का मान ज्ञात कीजिए।

Answer» `|cosx|={{:(cosx",",0lexlepi//2),(-cosx",",(pi)/(2)lexlepi):}`
`therefore" "int_(0)^(pi)|cosx|dx=int_(0)^(pi//2)|cosx|dx+int_(pi//2)^(pi)|cosx|dx`
`=int_(0)^(pi//2)cosx dx-int_(pi//2)^(pi)cosx dx`
`=[sinx]_(0)^(pi//2)-[sinx]_(pi//2)^(pi)`
`=(sin.(pi)/(2)-sin0)-(sinpi-sin.(pi)/(2))`
`=1-0-(0-1)=2`


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