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`int_(0)^(pi)|cosx|dx` का मान ज्ञात कीजिए। |
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Answer» `|cosx|={{:(cosx",",0lexlepi//2),(-cosx",",(pi)/(2)lexlepi):}` `therefore" "int_(0)^(pi)|cosx|dx=int_(0)^(pi//2)|cosx|dx+int_(pi//2)^(pi)|cosx|dx` `=int_(0)^(pi//2)cosx dx-int_(pi//2)^(pi)cosx dx` `=[sinx]_(0)^(pi//2)-[sinx]_(pi//2)^(pi)` `=(sin.(pi)/(2)-sin0)-(sinpi-sin.(pi)/(2))` `=1-0-(0-1)=2` |
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