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int_0^picos^3xdx

Answer»

SOLUTION :`int_0^picos^3xdx=int_0^pi(cos3x+3cosx)/4dx`
=`1/4[int_0^picos3xdx+3int_0^picosxdx]`
=`1/4{[1/3sin3x]_0^pi+3[SINX]_0^pi}`
=`1/12(sin3pi-sin0)+3/4(sinpi-sin0)=0`


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