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int_(0)^(pi/4) sin 2x dx |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`" Let I "= int_(0)^(pi//4) sin 2 x dx` <br/> `=int_(0)^(pi//4) 2 sin x <a href="https://interviewquestions.tuteehub.com/tag/cosx-936418" style="font-weight:bold;" target="_blank" title="Click to know more about COSX">COSX</a> dx `<br/> `<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(x=0 ""rArr t=sin 0=0)underset(x=(pi)/(4) ""rArr t= sin.(pi)/(4) =(1)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2)))("Letsin "x=t ""rArr cosx dx =dt)` <br/> `:. I=2 int_(0)^(pi//sqrt(2))t dt = 2 [(t^(2))/(2)]_(0)^(1//sqrt(2))` <br/> `=((1)/(sqrt(2)))^(2)=(1)/(2)`</body></html> | |