1.

\( \int_{-1}^{0}\left(x^{2}+1\right) \cdot d\left(x^{2}+1\right) \)

Answer»

Let I = \(\int\limits_{-1}^0\)(x2 + 1) d (x2 + 1)

Let x2 + 1 = t

d(x2 + 1) = dt

Limit converts from

t = (-1)2 + 1 = 1 + 1 = 2

to t = 02 + 1 = 1

∴ I = \(\int\limits_2^1tdt\) = \([\frac{t^2}2]_2^1\) = (1/2 - 1/4) = -3/2

Alternative:

\(\int\limits_{-1}^0(x^2+1)d(x^2+1)\) \([\frac{(x^2+1)^2}2]_{-1}^0\)

 = \((\frac12-\frac42)\) = -3/2



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