\int _ { - 1 } ^ { 1 } ( x + 1 ) d x – InterviewSolution

1.	\int _ { - 1 } ^ { 1 } ( x + 1 ) d x
Answer» integration((x+1)dx)-1 to 1=(x^2/2+x)-1 to 1=1/2(1-1)+(1+1)=0+2=2

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