1.

int (1)/(1 - x^(2)) " ln " ((1 + x)/(1 -x))dx =

Answer»

`(1)/(2) "In" ((1 + X)/(1 - x))^(2) + C`
`(1)/(4) [ "In" ((1 + x)/(1 - x)) ]^(2) + C `
`(1)/(3) "In" ((1 + x)/(1 - x)) + C `
`(1)/(2) [ "In" ((1+ x)/(1 - x) ) ]^(3) ` + C

Answer :B


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