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`int_(1)^(2)(cos(logx))/(x)dx` का मान ज्ञात कीजिए । |
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Answer» माना `logx=t" "rArr" "(1)/(x)dx=dt` `x = a" पर "t=log 1=0` `x = 2 " पर "t=log2` `therefore int_(1)^(2)(cos(logx))/(x)dx=int_(0)^(log2)cos tdt` `=[sint]_(0)^(log2)=sin(log2)-sin 0` `=sin(log2)` |
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