1.

`int(1)/(cos(x+a).sin(x+b))dx` का मान ज्ञात कीजिए ।

Answer» `int(1)/(cos(x+a).sin(x+b))dx`
`" "=(1)/(cos(a-b))int(cos(a-b))/(cos(x+a).sin(x+b))dx`
`" "=(1)/(cos(a-b))int(cos{(x+a)-(x+b)})/(cos(x+a).sin(x+b))dx`
`" "=(1)/(cos(a-b))int(+sin(x+a)sin(x+b))/(cos(x+a)sin(x+b))dx`
`" "=(1)/(cos(a-b))int{(cos(x+a)cos(x+b))/(cos(x+a)sin(x+b))+(sin(x+a)sin(x+b))/(cos(x+a)sin(x+b))}dx`
`" "=(1)/(cos(a-b))int{cot(x+b)+tan(x+a)}dx`
`" "=(1)/(cos(a-b))[log|sin(x+b)|+log|sec(x+a)|]+c`


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