InterviewSolution
Saved Bookmarks
| 1. |
`int(1)/(cos(x+a).sin(x+b))dx` का मान ज्ञात कीजिए । |
|
Answer» `int(1)/(cos(x+a).sin(x+b))dx` `" "=(1)/(cos(a-b))int(cos(a-b))/(cos(x+a).sin(x+b))dx` `" "=(1)/(cos(a-b))int(cos{(x+a)-(x+b)})/(cos(x+a).sin(x+b))dx` `" "=(1)/(cos(a-b))int(+sin(x+a)sin(x+b))/(cos(x+a)sin(x+b))dx` `" "=(1)/(cos(a-b))int{(cos(x+a)cos(x+b))/(cos(x+a)sin(x+b))+(sin(x+a)sin(x+b))/(cos(x+a)sin(x+b))}dx` `" "=(1)/(cos(a-b))int{cot(x+b)+tan(x+a)}dx` `" "=(1)/(cos(a-b))[log|sin(x+b)|+log|sec(x+a)|]+c` |
|