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`int(1)/(e^(x)-1)dx` का मान ज्ञात कीजिए । |
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Answer» माना `I=int(1)/(e^(x)-1)dx=int(e^(-x))/(e^(-x)(e^(x)-1))dx` `" "=int(e^(-x))/(1-e^(-x))dx` माना`1-e^(-x)=t` `rArr" "e^(-x)=(dt)/(dx)` `rArr" "e^(-x)dx=dt` `therefore" "I=int(dt)/(t)=log|t|+c` `" "=log|1-e^(-x)|+c` |
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