InterviewSolution
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`int[(1)/(logx)-(1)/((logx)^(2))]dx` का मान ज्ञात कीजिए । |
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Answer» `int[(1)/(logx)-(1)/((logx)^(2))]dx=int1.(1)/(logx)dx-int(1)/((logx)^(2))dx` `=(1)/(logx).int1dx - int{(d)/(dx).(1)/(logx).int1dx}dx-int(1)/((logx)^(2))dx` `=(x)/(logx)-int(-1)/(x(logx)^(2)).xdx-int(1)/((logx)^(2))dx+c` `=(x)/(logx)+int(1)/((logx)^(2))dx- int(1)/((logx)^(2))dx+c = (x)/(logx)+c` |
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