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`int((1+logx)^(2))/(x)` का मान ज्ञात कीजिए ।

Answer» माना `I=int((1+logx)^(2))/(x)dx`
माना `1+logx=t`
`rArr" "(1)/(x)=(dt)/(dx)`
`rArr" "(1)/(x)dx=dt`
`therefore" "I=int t^(2)dt=(1)/(3)t^(3)+c`
`" "=(1)/(3)(1+logx)^(3)+c`


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