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`int((1+logx)^(2))/(x)` का मान ज्ञात कीजिए । |
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Answer» माना `I=int((1+logx)^(2))/(x)dx` माना `1+logx=t` `rArr" "(1)/(x)=(dt)/(dx)` `rArr" "(1)/(x)dx=dt` `therefore" "I=int t^(2)dt=(1)/(3)t^(3)+c` `" "=(1)/(3)(1+logx)^(3)+c` |
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