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`int(1-tanx)/(1+tanx)dx` का मान ज्ञात कीजिए । |
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Answer» माना `I=int(1-tanx)/(1+tanx)dx=int(cosx-sinx)/(cosx+sinx)dx` माना `cosx+sinx+t` `rArr" "-sinx+cosx=(dt)/(dx)` `rArr" "(cosx-sinx)dx=dt` `therefore" "I=int(1)/(t)dt=log|t|+c` `" "=log|cosx+sinx|+c` |
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