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`int(1-tanx)/(1+tanx)dx` का मान ज्ञात कीजिए ।

Answer» माना `I=int(1-tanx)/(1+tanx)dx=int(cosx-sinx)/(cosx+sinx)dx`
माना `cosx+sinx+t`
`rArr" "-sinx+cosx=(dt)/(dx)`
`rArr" "(cosx-sinx)dx=dt`
`therefore" "I=int(1)/(t)dt=log|t|+c`
`" "=log|cosx+sinx|+c`


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