`int(1+tanx)/(e^(-x)cosx)dx` is equal toA. `e^(-x)tanx+C`B. `e^(-x)secx+C`C. `e^(x)sec x+C`D. `e^(x)tanx+C`

`int(1+tanx)/(e^(-x)cosx)dx` is equal toA. `e^(-x)tanx+C`B. `e^(-x)sec

1.	`int(1+tanx)/(e^(-x)cosx)dx` is equal toA. `e^(-x)tanx+C`B. `e^(-x)secx+C`C. `e^(x)sec x+C`D. `e^(x)tanx+C`
Answer» Correct Answer - C Let `l=int e^(x) sec x dx +int e^(x) sec x tan x dx` On integration by parts, we get `e^(x)secx - int e^(x) sec x tan x dx+int e^(x)sec x tan x dx+C` `=e^(x)secx+C`