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`int(1)/(x)(log_(ex)e)dx` is equal toA. `log_(e)(1-log_(e)x)+C`B. `log_(e)(log_(e)ex-1)+C`C. `log_(e)(log_(e)x-1)+C`D. `log_(e)(log_(e)x+1)+C` |
Answer» Correct Answer - D Let `l=int(1)/(x)(log_(ex)e)dx=int(1)/(x(1+log_(e)x))dx` Put `log_(e)x=t" "rArr" "(1)/(x)dx=dt` `therefore" "l=int(dt)/((1+t))=log_(e)(1+t)+C` `=log_(e)(1+log_(e)x)+C` |
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