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`int (1)/(x(logx)^(m) )dx,x gt 0, m ne 1` |
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Answer» `int(1)/(x(logx)^(m))dx" माना "logx=t` `=int(1)/(t^(m))dt=intt^(-m)dt" "rArr (1)/(x)dx=dt` `=(t^(-m+1))/(-m+1)+c=((logx)^(1-m))/(1-m)+c` |
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