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`int(10 x^9+10 x^x(log)_(e^(10))dx)/(x^(10)+10^x)` equalsA. `10^(x)-x^(10)+c`B. `10^(x) +x^(10)+c`C. `(10^(x) -x^(10))^(-1)+c`D. `log (10^(x) +x^(10))+c` |
Answer» Correct Answer - D `int [(10 x^(9) +10^(x)log _(e) 10)/(x^(10)+10^(x))]dx` ` " Let " x^(10) +10^(x) =t rArr (10x^(9) +10^(x) log_(e) 10) dx=dt` `=int (1)/(t) dt= log | t| +c` ` = log |x^(10)+ 10^(x)| +c` lt brgt |
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