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`int(2x^(2)+3)/((x^(2)-1)(x^(2)+4))dx=alog((x+1)/(x-1))+b"tan"^(-1)(x)/(2)` , then (a,b) isA. `(1, -1)`B. `(-1, 1)`C. `((1)/(2),-(1)/(2))`D. `((1)/(2),(1)/(2))` |
Answer» Correct Answer - D Let `l=int(2x^(2)+3)/((x^(2)-1)(x^(2)+4))dx=int(dx)/(x^(2)-1)+int(dx)/(x^(2)+4)` `" "[because (2x^(2)+3)/((x^(2)-1)(x^(2)+4))=(1)/(x^(2)-1)+(1)/(x^(2)+4)]` `rArr" "l=(1)/(2)log((x-1)/(x+1))+(1)/(2)tan^(-1).(x)/(2)+C` `But" "l=a log((x-1)/(x+1))+b tan^(-1)((x)/(2))+C` `therefore" "a=(1)/(2), b=(1)/(2)` |
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