1.

int_-a^a(x^5+2x^2+x)dx

Answer»

SOLUTION :`int_-a^a(x^5+2x^2+x)DX=[x^6/6+(2x^3)/3+(2x^2)/2]_-a^a`
=`1/6(a^6-a^6)+2/3(a^3+a^3)+(a^2-a^2)=(4a^3)/3`


Discussion

No Comment Found

Related InterviewSolutions