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int_-a^a(x^5+2x^2+x)dx |
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Answer» SOLUTION :`int_-a^a(x^5+2x^2+x)DX=[x^6/6+(2x^3)/3+(2x^2)/2]_-a^a` =`1/6(a^6-a^6)+2/3(a^3+a^3)+(a^2-a^2)=(4a^3)/3` |
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