1.

int(cos^4x-sin^4x)/(cosx-sinx)dx

Answer»

SOLUTION :`INT(cos^4-sin^4x)/(cosx-sinx)DX`
=int((cos^2x+sin^2x)(cosx-sinx)(cosx+sinx)dx)/(cosx-sinx)`
=`int(cosx+sinx)dx=sinx-cosx+C`


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