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int(cos^4x-sin^4x)/(cosx-sinx)dx |
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Answer» SOLUTION :`INT(cos^4-sin^4x)/(cosx-sinx)DX` =int((cos^2x+sin^2x)(cosx-sinx)(cosx+sinx)dx)/(cosx-sinx)` =`int(cosx+sinx)dx=sinx-cosx+C` |
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