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`int (cos 5x + cos 4x)/(1-2cos3x) dx`A. `(sin2x)/(2)+cosx+c`B. `(sin2x)/(2)-cosx+c`C. `-(sin2x)/(2)-sinx+c`D. `(sin2x)/(2)-cosx+c` |
Answer» Correct Answer - C `I=int(cos5x+cos4x)/(1-2cos3x)dx=int(2"cos"(9x)/(2)"cos"(x)/(2))/(1-2(2"cos"^(2)(3x)/(2)-1))dx` `=int(2"cos"(9x)/(2)"cos"(x)/(2))/(3-4"cos"^(2)(3x)/(2))dx` `=int(2"cos"(9x)/(2)"cos"(x)/(2)"cos"(3x)/(2))/(3"cos"(3x)/(2)-4"cos"^(3)(3x)/(2))dx` `=int(2"cos"(9x)/(2)"cos"(3x)/(2)"cos"(x)/(2))/(-"cos"(9x)/(2))dx` `=-int 2"cos"(3x)/(2)"cos"(x)/(2)dx` `=-int(cos2x+cosx)dx` `=-(sin2x)/(2)-sinx+c` |
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