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`int ((cos2x-cos2alpha)/(cosx-cosalpha))dx` का मान ज्ञात कीजिए ।

Answer» `int((cos2x-cos2alpha)/(cosx-cosalpha))dx`
`=int((2cos^(2)x-1)-(2cos^(2)alpha-1))/((cosx-cosalpha))dx`
`=2int((cos^(2)x-cos^(2)alpha))/((cosx-cosalpha))=2int(cosx+cosalpha)dx`
`=2intcosx dx+2cosalpha* intdx`
`=2sinx+2xcosalpha + c`


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