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`int ((cos2x-cos2alpha)/(cosx-cosalpha))dx` का मान ज्ञात कीजिए । |
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Answer» `int((cos2x-cos2alpha)/(cosx-cosalpha))dx` `=int((2cos^(2)x-1)-(2cos^(2)alpha-1))/((cosx-cosalpha))dx` `=2int((cos^(2)x-cos^(2)alpha))/((cosx-cosalpha))=2int(cosx+cosalpha)dx` `=2intcosx dx+2cosalpha* intdx` `=2sinx+2xcosalpha + c` |
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