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int(cos2x)/(sin^2x xxcos^2x)dx |
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Answer» SOLUTION :`INT(COS2X)/(sin^2x xxcos^2x)DX` =`int(cos^2x-sin^2x)/(sin^2x:cos^2x)dx` =`int(cosec^2x-sec^2x)dx` =`-cotx-tanx+C` |
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