1.

int(cos3xcos2x+sin3xsin2x)/(1-cos^2)dx

Answer»

SOLUTION :`INT(cos3xcos2x+sin3xsin2x)/(1-cos^2)DX`
=`INTCOS(3x-2x)/(1-cos^2x)dx`
=`intcosx/sin^2xdx=int1/sinx.cosx/sinx dx`
=`intcosecx.cotxdx=-cosecx+C`


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