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int(cos3xcos2x+sin3xsin2x)/(1-cos^2)dx |
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Answer» SOLUTION :`INT(cos3xcos2x+sin3xsin2x)/(1-cos^2)DX` =`INTCOS(3x-2x)/(1-cos^2x)dx` =`intcosx/sin^2xdx=int1/sinx.cosx/sinx dx` =`intcosecx.cotxdx=-cosecx+C` |
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