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int(cospx+cosqx)/(sinpx+sinqx)dx |
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Answer» SOLUTION :`INT(cospx+cosqx)/(sinpx+sinqx)dx` =`int(2COS((p+q)/2)x.cos((p-q)/2)x)/(2SIN((p+q)/2)x.cos((p-q)/2)x)dx` =`intcot((p+q)/2)xdx` =2/(p+q) Inabs(sin((p+q)/2)x)+C` |
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