1.

int(cospx+cosqx)/(sinpx+sinqx)dx

Answer»

SOLUTION :`INT(cospx+cosqx)/(sinpx+sinqx)dx`
=`int(2COS((p+q)/2)x.cos((p-q)/2)x)/(2SIN((p+q)/2)x.cos((p-q)/2)x)dx`
=`intcot((p+q)/2)xdx`
=2/(p+q) Inabs(sin((p+q)/2)x)+C`


Discussion

No Comment Found

Related InterviewSolutions