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`int(cosx)/(1+cosx)dx` |
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Answer» `int(cosx)/(1+cosx)dx` `=int((1+cosx)-1)/(1+cosx)dx` `=int1dx- int(1)/(1+cosx)dx` `=int1dx -int(1)/(2cos^(2).(x)/(2))dx` `=int 1dx -(1)/(2)intsec^(2).(x)/(2)dx` `=x-(1)/(2)(tan.(x)/(2))/(1//2)+c=x-tan.(x)/(2)+c` |
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