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`int((cosx)^(n-1))/((sinx)^(n+1))dx=` (A) `-cot^n x/n+c` (B) `-cot^n x/(n+1)+c` (C) `cot^n x/n+c` (D) `cot^n x/(n+1)+c`A. `(cot^(n)x)/(n)`B. `(-cot^(n-1)x)/(n-1)`C. `(-cot^(n)x)/(n)`D. `(cot^(n-1)x)/(n-1)` |
Answer» Correct Answer - C `int(cos^(n-1)x)/(sin^(n+1)x)dx=int cot^(n-1)x" cosec"^(2)xdx` `=(-cot^(n)x)/(n)+C` |
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