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`int(dx)/((1+sqrtx)^(2010))=2[(1)/(alpha(1+sqrtx)^(alpha))-(1)/(beta(1+sqrtx))^(beta)]+c` where `alpha, betagt0" then "alpha-beta` isA. 1B. 2C. `-1`D. `-2` |
Answer» Correct Answer - A `int(dx)/((1+sqrtx)^(2010))` `=int(sqrtx)/(sqrtx(1+sqrtx)^(2010))dx` `=2int(t-1)/(t^(2010))dt(t=1+sqrtx)` `=2[(1)/(2009t^(2006))-(1)/(2008t^(2008))]+c` `rArr" "alpha=2009, beta=2008` |
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