1.

int(dx)/(sinx+sin2x)=

Answer»

`1/6log(1-cosx)+1/2log(1+cosx)+2/3log\|1+2cosx|+C`
`1/6log(1-cosx)-1/2log(1+cosx)-2/3log\|1+2cosx|+c`
`1/6log(1-cosx)+1/2log(1+cosx)-2/3log\|1+2cosx|+c`
`1/6log[(1-cosx)(1+cosx)|1+2cosx|]+c`

ANSWER :C


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