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`int(dx)/(xsqrt(x^(6)-16))=`A. `sec.(x^(3))/(4)+c`B. `(1)/(12)sec.(x^(3))/(4)+c`C. `(1)/(3)sec.(x^(3))/(4)+c`D. none of these |
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Answer» Correct Answer - B `int(dx)/(xsqrt(x^(6)-16))=int(x^(2)dx)/(x^(3)sqrt(x^(6)-16))` `=(1)/(3)int(dt)/(sqrt(t^(2)-16))" "("putting "x^(3)=t)` `=(1)/(48)int(dt)/((1)/(4)sqrt((t^(2))/(16)-1))` `=(1)/(12)sec.(t)/(4)+c` `=(1)/(12)sec. (x^(3))/(4)+c` |
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