1.

int e^(sinx).sin2x dx =

Answer»

`2e^("SINX")`(sinx + 1) + C
`e^("sinx")` (sinx +2) + c
`e^("sinx")` (2sinx - 2) + c
`e^("sinx")` (3 sinx - 2) +c

Answer :C


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