1.

int e^(x) [ "In " x + (1)/(x^(2)) ]dx =

Answer»

`e^(x) `Inx+ C
`e^(x) ( "In "x- (1)/(x) ) + c`
`e^(x) [ "In " x - (1)/(x^(2)) ] + c `
`(e^(x))/(x^(2)) + c`

Answer :B


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