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\(\int\frac{dx}{x^2+16}=\)∫dx/(x2+16) = (A) \(\frac{1}{4}\)tan-1\(\frac{x}{4}\) + K(B) \(\frac{1}{4}\)tan-1\(x\) + K(C) tan-1\(\frac{x}{4}\) + K(D) tan-1\(\frac{x-4}{4}\) + K |
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Answer» Option : (A) \(\frac{1}{4}\)tan-1\(\frac{x}{4}\) + K |
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