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\(\int\frac{dx}{x^2-9}=\)∫dx/(x2-9) = (A) \(\frac{1}{6}\)log\(|\frac{x+3}{x-3}|\) + K(B) tan-1(x2 – 9) + K(C) \(\frac{1}{6}\)log\(|\frac{x-3}{x+3}|\) + K(D) sin-1\(\frac{x}{3}\) + K |
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Answer» Option : (C) \(\frac{1}{6}\)log\(|\frac{x-3}{x+3}|\) + K |
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