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int(Inx)/x^5dx

Answer»

Solution :`int(INX)/x^5dx=int1nx.x^-5dx`
[TAKE 1n x as FIRST and `x^-5` as second function]
=`1nx.x^-4/-4-int1/x.x^-4/-4dx`
=`-(1n x)/(4x^4) +1/4intx^-5dx`
=`-(1nx)/(4x^4)+1/4 x^-4/-4+C`
=`-(1nx)/(4x^4)-1/(16x^4)+C`


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