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int_(-pi//4)^(n pi - pi/4) | sin x + cos x | dx ( n in N)is : |
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Answer» 0 ` x + pi/4=t rArr dx = dt` `= sqrt2 int_0^(N pi)|sin t|dx = n sqrt2 int_0^pi sin t dt` ` = n sqrt2 (-COS t)_0^pi = n sqrt2(1-(-1))` ` = 2SQRT2 n` |
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