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int_(-pi/4)^(pi/4)cos^2xdx |
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Answer» SOLUTION :`int_(-pi/4)^(pi/4)cos^2xdx=int_(-pi/4)^(pi/4)[(1+cosx)/2]dx` =`1/2int_(-pi/4)^(pi/4)dx+1/2int_(-pi/4)^(pi/4)COS2XDX` =`1/2[x]_(-pi/4)^(pi/4)+1/4[sin2x]_(-pi/4)^(pi/4)` =`1/2(pi/4+pi/4)+1/4(SIN(pi/4)+sin(pi/4))=pi/4+1/2` |
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