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`int_(pi//6)^(pi//3) sin(3x)dx=`A. `(1)/(3)`B. `-(1)/(3)`C. `1`D. `3` |
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Answer» Correct Answer - A `(-cos 3x)/(3):|_(pi//6)^(pi//3)=(1)/(3)(-1-0)=(1)/(3)`. |
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