1.

int_(-pi/6)^(pi/6)sin^5xdx

Answer»

Solution :Let `F(x)=sin^5x`
Then`f(-x)=sin^5(-x)`
=`-sin^5x=-f(x)`
So f(x) is an odd FUNCTION.
Thus `int_-a^af(x)dx=0`
`therefore int_(-pi/6)^(pi/6) sin^5xdx=0`


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