InterviewSolution
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int_(-pi/6)^(pi/6)sin^5xdx |
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Answer» Solution :Let `F(x)=sin^5x` Then`f(-x)=sin^5(-x)` =`-sin^5x=-f(x)` So f(x) is an odd FUNCTION. Thus `int_-a^af(x)dx=0` `therefore int_(-pi/6)^(pi/6) sin^5xdx=0` |
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