`int(root3(x))(root5(1+root3(x^(4))))dx` is equal toA. `(1+x^((3)/(4)))^((6)/(5))+C`B. `(1+x^((4)/(3)))^((6)/(5))+C`C. `(5)/(8)(1+x^((4)/(3)))^((6)/(5))+C`D. `(1)/(6)(1+x^((4)/(3)))^(6)+C`

`int(root3(x))(root5(1+root3(x^(4))))dx` is equal toA. `(1+x^((3)/(4))

1.	`int(root3(x))(root5(1+root3(x^(4))))dx` is equal toA. `(1+x^((3)/(4)))^((6)/(5))+C`B. `(1+x^((4)/(3)))^((6)/(5))+C`C. `(5)/(8)(1+x^((4)/(3)))^((6)/(5))+C`D. `(1)/(6)(1+x^((4)/(3)))^(6)+C`
Answer» Correct Answer - C Let `l=int(root3(x))(root5(1+root3(x^(4))))dx` Put `root3(x)^(4)=t rArr (4)/(3).root3x dx=dt` `therefore" "l=(3)/(4)int(root5(1+t))dt=(3)/(4)[((1+t)^((1)/(5)+1))/((1)/(5)+1)]+C` `=(5)/(8)[(1+root3(x)^(4))^(6//5)]+C`