InterviewSolution
Saved Bookmarks
| 1. |
`int(sec^(2)x)/("cosec"^(2)x)dx` |
|
Answer» `int(sec^(2)x)/("cosec"^(2)x)dx=int(sin^(2)x)/(cos^(2)x)dx` `=int tan^(2) xdx= int (sec^(2)x-1)dx` `=intsec^(2)x dx - int 1.dx` `=tan x-x+c` |
|